Centripetal Force through Turns

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Homework Help Overview

The problem involves a car navigating a tight turn with a specified radius, mass, and coefficient of static friction. Participants are exploring the application of static friction in the context of circular motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the use of the coefficient of static friction despite the car being in motion, considering the transition from straight to curved motion. There is discussion about the role of static versus dynamic friction in maintaining circular motion.

Discussion Status

There is an ongoing exploration of the reasoning behind using static friction in this scenario, with participants providing insights into the conditions under which the coefficient may change. Multiple interpretations regarding the frictional forces involved are being discussed.

Contextual Notes

Participants note that the wheels are spinning while maintaining static contact with the road, and the discussion includes the implications of losing grip during the turn.

RiskX
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Hi,

I face some difficulties trying to solve the following problem:

"You’re sitting in the passenger seat of the car, approaching
a tight turn with a 10.0-meter radius. You know that the coefficient of static
friction is 0.8 on this road (you use the coefficient of static
friction because the tires aren’t slipping on the road’s surface) and that the
car has a mass of about 1,000 kg. What’s the maximum speed the driver can
go and still keep you safe?"

I didn't understand why we use the coefficient of static fricftion if the car is already on a run... Is that beacuse the surface has changed from a stright plane to a curved one?
 
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RiskX said:
Hi,

I face some difficulties trying to solve the following problem:

"You’re sitting in the passenger seat of the car, approaching
a tight turn with a 10.0-meter radius. You know that the coefficient of static
friction is 0.8 on this road (you use the coefficient of static
friction because the tires aren’t slipping on the road’s surface) and that the
car has a mass of about 1,000 kg. What’s the maximum speed the driver can
go and still keep you safe?"

I didn't understand why we use the coefficient of static fricftion if the car is already on a run... Is that beacuse the surface has changed from a stright plane to a curved one?

Because it is that friction force that keeps the car in circular motion.
 
RiskX said:
I didn't understand why we use the coefficient of static fricftion if the car is already on a run... Is that beacuse the surface has changed from a stright plane to a curved one?

I am not sure but I guess you mean why use the static coeficient instead of the dynamic.

Note that the wheels are spining and in fact their surface is statically adhered to the road surface. Only if the car looses grip (for example going too fast in the turn) and starts to slide the coeficient changes.
 
gonzacf said:
I am not sure but I guess you mean why use the static coeficient instead of the dynamic.

Note that the wheels are spining and in fact their surface is statically adhered to the road surface. Only if the car looses grip (for example going too fast in the turn) and starts to slide the coeficient changes.

The dynamic friction as the car rotates along the circle should equal the driving motor force ( in opposite direction ) for tangential acceleration to be zero.

So that uniform circular motion criteria are met.
 

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