Centripetal Force through Turns

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SUMMARY

The discussion centers on calculating the maximum speed a car can maintain while navigating a turn with a radius of 10.0 meters, given a static friction coefficient of 0.8 and a car mass of 1,000 kg. Participants clarify that the coefficient of static friction is relevant because it ensures the tires maintain grip on the road during the turn, preventing slipping. The conversation emphasizes that the dynamic friction coefficient only becomes relevant if the car exceeds the maximum speed and begins to slide.

PREREQUISITES
  • Understanding of centripetal force and circular motion
  • Knowledge of static and dynamic friction coefficients
  • Basic physics concepts related to mass and acceleration
  • Familiarity with the equations of motion in physics
NEXT STEPS
  • Study the equations for centripetal acceleration and force
  • Learn about the differences between static and dynamic friction coefficients
  • Explore the implications of friction in vehicle dynamics
  • Investigate real-world applications of circular motion in automotive engineering
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding vehicle dynamics and the principles of motion during turns.

RiskX
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Hi,

I face some difficulties trying to solve the following problem:

"You’re sitting in the passenger seat of the car, approaching
a tight turn with a 10.0-meter radius. You know that the coefficient of static
friction is 0.8 on this road (you use the coefficient of static
friction because the tires aren’t slipping on the road’s surface) and that the
car has a mass of about 1,000 kg. What’s the maximum speed the driver can
go and still keep you safe?"

I didn't understand why we use the coefficient of static fricftion if the car is already on a run... Is that beacuse the surface has changed from a stright plane to a curved one?
 
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RiskX said:
Hi,

I face some difficulties trying to solve the following problem:

"You’re sitting in the passenger seat of the car, approaching
a tight turn with a 10.0-meter radius. You know that the coefficient of static
friction is 0.8 on this road (you use the coefficient of static
friction because the tires aren’t slipping on the road’s surface) and that the
car has a mass of about 1,000 kg. What’s the maximum speed the driver can
go and still keep you safe?"

I didn't understand why we use the coefficient of static fricftion if the car is already on a run... Is that beacuse the surface has changed from a stright plane to a curved one?

Because it is that friction force that keeps the car in circular motion.
 
RiskX said:
I didn't understand why we use the coefficient of static fricftion if the car is already on a run... Is that beacuse the surface has changed from a stright plane to a curved one?

I am not sure but I guess you mean why use the static coeficient instead of the dynamic.

Note that the wheels are spining and in fact their surface is statically adhered to the road surface. Only if the car looses grip (for example going too fast in the turn) and starts to slide the coeficient changes.
 
gonzacf said:
I am not sure but I guess you mean why use the static coeficient instead of the dynamic.

Note that the wheels are spining and in fact their surface is statically adhered to the road surface. Only if the car looses grip (for example going too fast in the turn) and starts to slide the coeficient changes.

The dynamic friction as the car rotates along the circle should equal the driving motor force ( in opposite direction ) for tangential acceleration to be zero.

So that uniform circular motion criteria are met.
 

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