Centripetal Motion Velocity vs. Position Angle Assignment

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Homework Help Overview

The discussion revolves around a problem in the context of centripetal motion, specifically focusing on the relationship between position vectors and instantaneous velocity vectors of particles moving in a uniform circular path. The original poster seeks to prove that the angle between two position vectors is equal to the angle between their corresponding velocity vectors without using calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the geometric relationship between position and velocity vectors in circular motion, with one suggesting the use of diagrams to visualize the problem. Questions arise regarding the angles formed between these vectors and the implications of circular motion on their orientation.

Discussion Status

The discussion is ongoing, with participants sharing insights and questioning the assumptions made in the problem. Some guidance has been offered regarding the use of diagrams, but there is no consensus on how to demonstrate the equality of the angles.

Contextual Notes

The problem is constrained by the requirement to avoid calculus and the lack of specific angle measurements, which may affect the approaches discussed.

burtonjib
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1. Show that the angle between two position vectors is equal to the angle between two instantaneous velocity vectors eg. v1 and v2 when v1 and v2 are conncected tail to tail in a uniform circle. No angles are given, it is just general.



2. Has to be proven without calculus. No information is given other than the fact that the circle is uniform and therefore the speed is constant.



3. I didn't attempt the question because I'm not exactly sure how to go by proving that the angles are equal.

 
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Do I understand you to be describing two particles in circular motion about a common central point? If so, then what is the angle between each particle's position vector and its velocity vector?
 
Yes that's exactly it. No angle was given though, the question is just asking to prove that the angle between position vectors is equal to that between the velocity vectors.
 
Try drawing a diagram. Draw arbitrary position vectors from a common point and then draw a velocity vector from the head of each position vector. Keep in mind that circular motion makes each velocity vector normal to its corresponding position vector.
 
I don't really see how that would show the equality between θ1 and θ2
 
If two lines intersect at an angle θ, at what angle do their normals intersect?
 

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