Centripetal vs centrifugal acceleration

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Homework Help Overview

The discussion revolves around the concepts of centripetal and centrifugal acceleration, particularly in the context of circular motion. The original poster expresses confusion about the differences between these two types of acceleration and how they relate to forces acting on objects in circular motion, using examples such as twirling a ball and carnival rides.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between centripetal and centrifugal forces, questioning whether they are opposite forces. They also explore a specific problem involving a carnival ride, considering the forces acting on a person in circular motion and how to calculate the minimum rotational speed to prevent falling.

Discussion Status

Some participants provide clarifications about the nature of centripetal and centrifugal forces, noting that centripetal force is a real force acting towards the center, while centrifugal force is described as a fictitious force perceived in a non-inertial frame. The original poster seeks confirmation on their problem setup, and one participant affirms the correctness of their analysis.

Contextual Notes

The discussion includes assumptions about the forces acting on a person in a carnival ride, such as the coefficient of friction and the radius of the circular motion, which are relevant to the calculations being discussed.

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i don't quite understand the difference between the two. i know centripetal means towards the middle and centrifugal goes out but i can't quite relate that to the problems.

for example, if you are twirling a ball on a string above your head in a circle, the centripetal acceleration points towards the middle and acts on the ball? but where is the centripetal acceleration? how does that figure into it?

are they just opposite forces?

in a related problem, its dealing with those spinning carnival rides where the floor drops from below you but you don't fall due to centripetal forces.

now the question says the coefficient of friction is .30 and the radius is 2.5 m, whatis the minimum rotational speed so you don't fall...this is what i have so far:

looking at a person on the ride, you have gravity (mg) down and friction upward. to make sure he doesn't fall you set the two forces equal to each other. now the friction is equal to the 0.30 times the normal force, which i believe in this case is the force due to centripetal acceleration (pushing the guy against the wall)? is that right (or is it centrifugal?) that equals mv^2/r.

so if i set mg = mv^2/r and the m's cancel out, i can solve for v. then i can convert that into a rotational speed? is my work correct?

thanks.
 
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The centripetal force is the force responsible for the maintenance of circular motion. So it's an actual force acting on the object and of course directed towards the center (centripetal=centre-seeking)

From the point of view of an object in circular motion, it seems as though there is a force which wants to pull it away from the center. This is called the centrifugal force. It is a ficticious force, so in reality not really a force at all. When we place ourselves in a noninertial frame there are all kinds of ficticious forces. Like on earth, because it spins it is not an inertial frame. We experience a centrifugal force, but also coriolis forces etc.

You know when a car accelerates you get pushed back into your seat? That's also a ficticious force. Nothing is pushing you backwards, rather, the seat is pushing you forward. The apparent force is ofcourse equal and opposite the real one. So also is the centrifugal force equal and opposite the actual centripetal force.
 
thanks - did i set up my problem correctly?
 
Friction = mu*Normal Reaction
and
Friction = mg
so
mg = mu*mv²/r

Other than that, your analysis of what's happening is absolutely correct
 

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