- #1

aspodkfpo

- 148

- 5

- Homework Statement
- Acceleration towards central axis? Where does extra normal force come from? Motion of the ball

- Relevant Equations
- a = v^2/r

Given such a diagram as shown above, we know that the normal force must be mg/sintheta. How is this normal force greater than the gravitational force conceptually? Is it due to the horizontal traveling (which must have been started by someone exerting a force?) compressing the sides of the cone such that they exert a force that can maintain horizontal motion?

Now, let's assume that the net force is slightly angled downwards towards the central axis such that the ball spirals down. Is this force still regarded as a centripetal force, or is a force directed towards the central axis in a 3D plane, rather than 2D never regarded as a centripetal force?

Add a downward velocity to the ball in the diagram such that the ball goes down the cone. According to solutions, " As r decreases the component of the velocity around the cone is too large for the object to follow circular path at the lower radius and the object will begin to move outwards and rise up the cone. " How does this work? Does the normal force get larger at the bottom and why would it?