Centripical acceloration question

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SUMMARY

The discussion focuses on calculating centripetal acceleration for a hawk flying in a horizontal arc with a radius of 10.7 meters at a constant speed of 3.75 m/s, yielding a centripetal acceleration of 1.31 m/s² using the formula Ac = v² / r. In the second part, the hawk accelerates at a rate of 1.30 m/s² while maintaining its circular path, requiring the combination of centripetal and tangential acceleration to determine the resultant acceleration vector. The confusion arises from the distinction between centripetal acceleration and total acceleration when speed increases.

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Homework Statement


Part 1. A hawk flies in a horizontal arc of radius 10.7m at a constant speed 3.75m/s. find the centripetal acceleration.

Part 2. It continues to fly along the same horizontal arc, but increases its speed at the rate of 1.30m/s^2. find the acceleration in this situation at the moment the harks speed is 3.75m/s.

acceleration
direction in degrees from direction of velocity towards center of circle


Homework Equations


Ac=v^2 / r


The Attempt at a Solution



Part1.
Ac=(3.75)^2 / 10.7 = 1.31m/s^2

Part 2.
Im very confused with this problemt because it says its accelorating to the same speed?
 
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Your part 1 looks good.
In part 2, it asks for the "acceleration", not just the "centripetal acceleration". The acceleration due to the speed increasing will be perpendicular to the centripetal acceleration, so you'll need a diagram to figure out the combination and its angle.
 

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