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## Homework Statement

Given a curve C that starts from the origin, goes to (1,0) then goes to (0,1), then back to the origin, find the centroid of the enclosed area D.

## Homework Equations

[tex]\bar{x} = {1/(2A)}*\int_C {x^2 dy}[/tex]

[tex]\bar{y} = -{1/(2A)}*\int_C {y^2 dx}[/tex]

## The Attempt at a Solution

Well, obviously the path of C is that of a triangle, and the area is 1/2, which means I have, for x-bar and y-bar, [tex]{1/4}\int_C {x^2 dy}[/tex] and [tex]{1/4}\int_C {y^2 dx}[/tex] respectively. My problem is: what are the upper and lower bounds for the line integral?

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