Dickfore
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It is. However, (c - v)/c \equiv \epsilon \sim 10^{-5} is compatible with SR and the experimental uncertainty of all these experiments.
The energy of a particle traveling at this close speed to c is:
<br /> \begin{array}{l}<br /> \frac{E}{m \, c^2} = \gamma = \left ( 1 - \frac{v^2}{c^2} \right)^{-\frac{1}{2}} \\<br /> <br /> = \left[ 1 - (1 - \epsilon)^2 \right]^{-\frac{1}{2}} \\<br /> <br /> = \left[ 2 \epsilon \, \left( 1 - \frac{\epsilon}{2}\right) \right]^{-\frac{1}{2}} \\<br /> <br /> \sim (2 \epsilon)^{-\frac{1}{2}} \, \left[1 + \frac{\epsilon}{4} + O(\epsilon^2) \right]<br /> \end{array} <br />
Considering the rest energy of neutrinos is of the order of 0.1 eV, this means that the energy of these neutrinos would be of the order of:
<br /> \frac{0.1 \, \mathrm{eV}}{\sqrt{2 \times 10^{-5}}} \sim 20 eV<br />
which is negligible. Even higher energies would bring the speed of neutrinos so close to c that the difference could not be detectable in any terrestrial experiment.
The energy of a particle traveling at this close speed to c is:
<br /> \begin{array}{l}<br /> \frac{E}{m \, c^2} = \gamma = \left ( 1 - \frac{v^2}{c^2} \right)^{-\frac{1}{2}} \\<br /> <br /> = \left[ 1 - (1 - \epsilon)^2 \right]^{-\frac{1}{2}} \\<br /> <br /> = \left[ 2 \epsilon \, \left( 1 - \frac{\epsilon}{2}\right) \right]^{-\frac{1}{2}} \\<br /> <br /> \sim (2 \epsilon)^{-\frac{1}{2}} \, \left[1 + \frac{\epsilon}{4} + O(\epsilon^2) \right]<br /> \end{array} <br />
Considering the rest energy of neutrinos is of the order of 0.1 eV, this means that the energy of these neutrinos would be of the order of:
<br /> \frac{0.1 \, \mathrm{eV}}{\sqrt{2 \times 10^{-5}}} \sim 20 eV<br />
which is negligible. Even higher energies would bring the speed of neutrinos so close to c that the difference could not be detectable in any terrestrial experiment.