CG of a cone ( using hollow cone)

  • Thread starter Thread starter VHAHAHA
  • Start date Start date
  • Tags Tags
    Cone
Click For Summary
SUMMARY

The discussion focuses on calculating the center of gravity (cg) of a solid cone using the center of gravity of a hollow cone. The user describes the process of determining the cg of a hollow cone, which is located at a height of h/3 (or r/3 * tant) from the base. By integrating the mass and volume of the hollow cones stacked to form the solid cone, the final center of gravity of the solid cone is derived as R * tant / 4, which is equivalent to H / 4. The horizontal coordinate of the center of mass for both the hollow and solid cones is confirmed to be zero.

PREREQUISITES
  • Understanding of center of gravity concepts
  • Familiarity with integration techniques in calculus
  • Knowledge of geometric properties of cones
  • Basic principles of density and volume calculations
NEXT STEPS
  • Study the derivation of the center of gravity for various geometric shapes
  • Learn about integration techniques for calculating volumes and masses
  • Explore applications of center of gravity in engineering and physics
  • Investigate the properties of hollow and solid cones in more detail
USEFUL FOR

Students in engineering and physics, mathematicians interested in calculus applications, and professionals involved in structural analysis and design.

VHAHAHA
Messages
58
Reaction score
0
The problem statement,
I know how to find the cg of a solid by using cross section
but i just don't know how to find the cg of the cone by using the cg of a hollow cone

for eg, we can calculate the cg of the half sphere by 1. calculating the cg of the hollow half sphere, than use it to calculate the cg of solid sphere

the problem is that i can't write a equation for the dm of each hollow cone because x and y changes

i just want to know how to do it and in fact this is not a homework question

can anyone help me please?
 
Physics news on Phys.org
I am assuming that the cone is right-circular, with an apex angle of t. Let's say that the cone is placed with its circular surface on the ground.
You can say that the solid cone is made of lots of hollow cones, one placed over the other.
Lets find the mass and cm of hollow-cone first, and then use integration to find cm of solid cone..
Hollow cone:
Hollow cone has its cm at a height of h/3(=r/3 *tant) from the bottom. Let the base of this hollow cone have inner radius 'r' and outer radius 'r+dr'.
Then, volume of hollow cone = d(volume of solid cone)
=d( (pi/3) r^3 tant) = pi*tant*r^2*dr. --> its mass = density*volume
Solid cone:
Therefore, cg of solid cone is
integral (r/3 *tant * pi *tant* r^2*dr*density)/integral(pi*tant*r^2*dr*density)
with the limits of r being 0 to R(base radius of solid cone).
You get the final answer as R*tant/4 which is same as H/4.

The horizontal cordinate of cm of hollow cone is zero... implies horizontal cordinate of cm of solid cone is also zero.

let me know if u understood this.. or need additional help
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
Replies
5
Views
1K
Replies
23
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
1
Views
1K
Replies
17
Views
1K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
7
Views
2K