- #1

Miraj Kayastha

- 80

- 0

## Homework Statement

During the ascent from a height R to a height 2R, the speed of the rocket changes

from 7600 m s–1 to 7320 m s–1. Show that, in SI units, the change ΔEK in the kinetic

energy of the rocket is given by the expression

ΔEk = (2.09 × 106)m.

m : mass of rocket

## Homework Equations

KE = 1/2 m.v^2

## The Attempt at a Solution

ΔEK= final ke - initial ke

= 1/2 m.7320^2 - 1/2 m. 7600^2

= - (2.09 × 10^6)m But the answer in the marking scheme is + (2.09 × 10^6)m.

Plz help and clarify the concept