Change in Classical Velocity of an Electron

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SUMMARY

The discussion focuses on calculating the change in classical velocity of an electron moving from a distance of 2 Å to 1 Å from a copper nucleus. The potential energy (PE) is calculated using the formula PE = (kq1q2)/r, leading to a change in PE of 1/2 J. This change in potential energy is equated to kinetic energy (KE), where KE = 1/2mv^2. The user seeks to solve for the change in velocity (v2 - v1) but expresses confusion regarding the calculations.

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  • Understanding of classical mechanics, specifically kinetic and potential energy concepts.
  • Familiarity with Coulomb's law and the formula for potential energy between charged particles.
  • Basic knowledge of algebraic manipulation to solve for variables in equations.
  • Concept of electron dynamics in atomic structures, particularly in relation to a nucleus.
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  • Study the derivation and application of Coulomb's law in electrostatics.
  • Learn how to calculate kinetic energy and its relationship with potential energy in classical mechanics.
  • Explore the concept of electron orbits and forces acting on electrons in atomic models.
  • Investigate the implications of changes in distance on the velocity of charged particles in electric fields.
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Students in physics, particularly those studying classical mechanics and electrostatics, as well as educators looking for examples of energy transformations in atomic systems.

merlinh
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Homework Statement


Copper nucleus at origin and an electron initially 2 A away from origin. Electron moved to 1A away from origin. What is the change in classical velocity of the electron?


Homework Equations


PE= (kq1q2)/r
change in PE from distance of 2A = KE



The Attempt at a Solution


change in PE from distance of 2A = KE
KE = 1/2mv^2
Change in PE =PE2-PE1=1/1-1/2= 1-1/2=1/2 J
KE=1/2m(v2-v1)^2=1/2 J
and solve for v2-v1?
I don't think I am understanding this right.
 
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merlinh said:

Homework Statement


Copper nucleus at origin and an electron initially 2 A away from origin. Electron moved to 1A away from origin. What is the change in classical velocity of the electron?


Homework Equations


PE= (kq1q2)/r
change in PE from distance of 2A = KE



The Attempt at a Solution


change in PE from distance of 2A = KE
KE = 1/2mv^2
Change in PE =PE2-PE1=1/1-1/2= 1-1/2=1/2 J
KE=1/2m(v2-v1)^2=1/2 J
and solve for v2-v1?
I don't think I am understanding this right.
I assume that the electron is orbiting the nucleus, you can use a certain equation to find the force on the electron, and you know how many protons copper nucleus has. use this to find the velocites.
 

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