Change in density of water with depth

Click For Summary
SUMMARY

The density of water increases by approximately 0.1813% at a depth of 3.7 km, calculated using the formula for pressure change (P = pgh) and the bulk modulus of water (b = 2 x 10^9 Pa). The original density of water is 1000 kg/m³, and the change in volume due to pressure is determined to be 1.813 x 10^-3. This change in volume directly correlates to the percentage increase in density, confirming that density increases with depth due to the incompressibility of water under pressure.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with the bulk modulus concept
  • Knowledge of pressure-volume relationships in liquids
  • Basic mathematical skills for percentage calculations
NEXT STEPS
  • Study the effects of pressure on the density of other fluids
  • Learn about the bulk modulus of different materials
  • Explore the implications of density changes in oceanography
  • Investigate the relationship between temperature, pressure, and density in fluids
USEFUL FOR

Students in physics or engineering, researchers in fluid dynamics, and professionals in oceanography or environmental science will benefit from this discussion.

dvolpe
Messages
34
Reaction score
0

Homework Statement


By what percentage does the density of water increase at a depth of 3.7 km below the surface?
(change in p/p)

Homework Equations


P = pgh where p = density
p of water = 1000 kg/m cubed
h = 3.7 km = 3700 m
bulk modulus of water (b) = 2 e 9

The Attempt at a Solution



b = - change in P/ (change in vol/vol orig)
or change in vol/vol original = -pgh/b
change in vol/vol original = 1.813 e -3
percent change in volume = .1813 percent

How does this relate to the percentage increase in density?
 
Last edited:
Physics news on Phys.org
dvolpe said:
How does this relate to the percentage increase in density?
If you have an original mass and you have an original volume, you can get the original density, yes? So now you have the same mass and a different volume, you can get THAT density, yes? Then calculate the difference, based on the original.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
4
Views
4K