- #1

yankeekd25

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## Homework Statement

A charge of +5.5 micro-Coulombs lies at x = -3.6 cm, y = 0 cm, a charge of +5.5 micro-Coulombs lies at x = +3.6 cm, y = 0 cm, a charge of +5.5 micro-Coulombs lies at x = 0 cm, y = +3.6 cm, and a charge of -5.5 micro-Coulombs lies at x = 0 cm, y = -3.6 cm. A charge of -6.5 micro-Coulombs moves from x = -3.6 cm, y = +3.6 cm to the x = -1.86 cm and y = +1.86 cm. What is the -6.5 micro-Coulomb charge's change in kinetic energy during this path? Answer in Joules.

## Homework Equations

Delta KE= - delta EPE

EPE= q V

V= Kq/r

## The Attempt at a Solution

I know I need to find the V that the four charges on the axis produce, but I'm not sure what to use for r, or what to do after that.