Change in linear Momentum(rebound)?

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SUMMARY

The discussion focuses on calculating the change in linear momentum of a superball with a mass of 84.1 g, dropped from a height of 3.6 m and rebounding to a height of 2.9 m. The acceleration due to gravity is 9.8 m/s². To find the change in linear momentum, one must determine the momentum just before and just after the collision with the floor, using the principles of free-fall to calculate the velocities at these points.

PREREQUISITES
  • Understanding of linear momentum and its formula (p = mv)
  • Knowledge of free-fall motion and gravitational acceleration
  • Ability to calculate potential energy and its conversion to kinetic energy
  • Familiarity with the concept of rebound height and its relation to velocity
NEXT STEPS
  • Calculate the velocity of the superball just before impact using the formula v = √(2gh)
  • Determine the velocity of the superball just after the bounce using the rebound height
  • Compute the change in linear momentum using the formula Δp = p_final - p_initial
  • Explore the effects of different materials on rebound height and momentum change
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and energy conservation in collisions.

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[SOLVED] Change in linear Momentum(rebound)?

A superball with a mass of 84.1 g is dropped from a height of 3.6 m. It rebounds to a height of 2.9 m. The acceleration of gravity is 9.8 m/s^2. What is the change in its linear momentum during the collision with the floor? Answer in units of kg m/s.

I got no idea how to attack this problem.
 
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The change in linear momentum during collision with the floor is ofcourse the momentum it had just after the bounce minus the momentum it had before it hit the floor.

Can you find these two momenta from the information given in the problem?
 
Do i need to use free-fall to find the velocity?
 

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