Change in momentum of baseball being struck

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Zach Lunch
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Homework Statement


A 0.33 kg softball has a velocity of 14 m/s at an angle of 50° below the horizontal just before making contact with the bat. What is the magnitude of the change in momentum of the ball while it is in contact with the bat if the ball leaves the bat with a velocity of (a) 15 m/s, vertically downward, and (b) 15 m/s, horizontally back toward the pitcher?

Homework Equations


→P=M*→V

The Attempt at a Solution


Find the Vector for momentum before hitting the bat .33<14*cos 50, 14*sin 50>
Subtract vector for each case. a) subtract .33<0,-15> b.) subtract .33<-15,0>
Then use Pythagorean Theorem to get magnitude sqrt(x^2 + y^2) for each case.
 
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Zach Lunch said:

Homework Statement


A 0.33 kg softball has a velocity of 14 m/s at an angle of 50° below the horizontal ...
Find the Vector for momentum before hitting the bat .33<14*cos 50, 14*sin 50>

The angle is 50° below the horizontal. The vertical component of the original momentum has to be negative.

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