Change in the Kinetic Energy of a System

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SUMMARY

The discussion focuses on calculating the change in kinetic energy (ΔK) of a pulley system involving a wooden block and a 100g mass. The kinetic energy is determined using the formula Ek = 1/2mv², where the change in kinetic energy is calculated as the difference between final and initial kinetic energy. Participants emphasize the importance of considering both masses in the system and the work-energy theorem, which states that ΔK equals the net work done (W_net) on the system. A detailed calculation of forces and a diagram are recommended for clarity.

PREREQUISITES
  • Understanding of the work-energy theorem
  • Familiarity with kinetic energy calculations
  • Knowledge of forces acting on a pulley system
  • Ability to interpret and create diagrams for physics problems
NEXT STEPS
  • Calculate the total kinetic energy for both the wooden block and the hanging mass
  • Determine the net work done on the system by analyzing all acting forces
  • Learn how to apply the work-energy theorem in practical scenarios
  • Create a diagram to visualize the forces and movements in the pulley system
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators teaching concepts related to kinetic energy and the work-energy theorem.

drewcila
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OP warned about not using the homework template
The question is to find the change in kinetic energy of a system. the system in use is a pully system with a wooden block on a flat surface attached to a 100g mass. I have calculated force of friction between the block and desk, and using a ticker timer, I have individual speeds at every 0.1 of a second. Additionally, the distance it travels is 45cm. We have to prove that the change in Kinetic energy is = work done in the system, so I can't use work as my answer.

I know that the equation for kinetic energy is Ek= 1/2mv2
Change in Kinetic energy is represented by the final Ek - initial Ek

I was thinking something like Ekf = 1/2(0.100)v22
then subtract Eki= 1/2(0.100)v12
I do not know what variables to use in this situation. do I use the mass of the block or the 100g mass apply force? and which velocity should I use? the speed at 0.1 seconds and 0.6 seconds? Does friction play into kinetic energy?
 
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drewcila said:
We have to prove that the change in Kinetic energy is = work done in the system, so I can't use work as my answer.
I am not sure what this means. It looks like you are asked to prove the work-energy theorem, ##\Delta K = W_{net}## so you do need to calculate work. Also, is your wooden block pulled by a hanging mass through a string over a pulley? If so, the change in kinetic energy is the difference in kinetic energy between two points in space. Your system has two moving masses, so you need to calculate the kinetic energy of each. Note that they are moving at the same speed at all times. So the left side of the equation is ##\Delta K=\Delta K_{wood}+\Delta K_{mass}##. You can calculate this and get a number.

The right side of the equation is the total work done by all the forces acting on the system. You need to figure out what forces do how much work on what parts of the system, calculate the numbers and add them all up. This number you get for the right side of the equation should be equal to the first number you got for the left side of the equation, ##\Delta K##.
 
Last edited:
A diagram would be helpful
 

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