Change of Basis Homework: Solving System of Equations

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SUMMARY

The discussion focuses on finding the change of basis matrix from basis vectors \(\beta\) to basis vectors \(\delta\) in the vector space \(V = \mathbb{R}^{1 \times 3}\). The equations derived from the problem state that \(\beta_{1} = \delta_{1} + \delta_{2} + \delta_{3}\), \(\beta_{2} = 3\delta_{1} + 3\delta_{2} + 4\delta_{3}\), and \(\beta_{3} = 3\delta_{1} + 4\delta_{2} + 3\delta_{3}\). To solve for the coefficients \(d_{ij}\) in the equations, one must set up a system of linear equations based on the relationships between the basis vectors.

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Homework Statement

We are given 2 bases for V = \Re_{1 x 3}. They are
\beta_{1} = \begin{bmatrix} 2 & 3 & 2\end{bmatrix}

\beta_{2} = \begin{bmatrix} 7 & 10 & 6\end{bmatrix}

\beta_{3} = \begin{bmatrix} 6 & 10 & 7\end{bmatrix}

and,

\delta_{1} = \begin{bmatrix} 1 & 1 & 1\end{bmatrix}

\delta_{2} = \begin{bmatrix} 0 & 1 & 1\end{bmatrix}

\delta_{3} = \begin{bmatrix} 1 & 1 & 0\end{bmatrix}

we are asked to find the \beta to \delta change of basis matrix.

The book says "by solving the relevant system of equations," you get

\beta_{1} = \delta_{1} + \delta_{2} + \delta_{3}

\beta_{2} = 3\delta_{1} + 3\delta_{2} + 4\delta_{3}

\beta_{3} = 3\delta_{1} + 4\delta_{2} + 3\delta_{3}


My question is WHAT system of equations did they solve to get the above?! I'm at a complete loss.

Homework Equations





The Attempt at a Solution


I know that for any vector \alpha, \alpha = b1\beta_{1} + b2\beta_{2} + b3\beta_{3} = d1\delta_{1} + d2\delta_{2} + d3\delta_{3}. Where do I go from there?
 
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They solved the 3 vector equations

\begin{align*}<br /> \beta_1 &amp;= d_{11} \delta_1 + d_{12} \delta_2 + d_{13} \delta 3 \\<br /> \beta_2 &amp;= d_{21} \delta_1 + d_{22} \delta_2 + d_{23} \delta 3 \\<br /> \beta_3 &amp;= d_{31} \delta_1 + d_{32} \delta_2 + d_{33} \delta 3<br /> \end{align*}<br />
 

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