Changing potential in harmonic oscillator

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SUMMARY

The discussion focuses on the transition of a particle's wavefunction in a harmonic oscillator when the potential changes from V_1(X)=\frac{1}{2}mw^2_1x^2 to V_2(X)=\frac{1}{2}mw^2_2(x-x_o)^2. It is established that immediately after the sudden change, the wavefunction remains unchanged, but as time progresses, it evolves to adapt to the new potential according to the Time-Dependent Schrödinger Equation (TDSE). This rapid change is classified as a diabatic process, indicating that the system's initial wavefunction corresponds to the first potential.

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  • Understanding of quantum mechanics principles, particularly harmonic oscillators.
  • Familiarity with the Time-Dependent Schrödinger Equation (TDSE).
  • Knowledge of wavefunction behavior under potential changes.
  • Concept of diabatic versus adiabatic processes in quantum systems.
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  • Study the implications of sudden changes in potentials on wavefunctions in quantum mechanics.
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facetten
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i have a quick question
A particle in ground state of a S.H.O whose potential is given by

[tex]V_1(X)=\frac{1}{2}mw^2_1x^2[/tex]
suddenly changes to

[tex]V_2(X)=\frac{1}{2}mw^2_2(x-x_o)^2[/tex]

what is the wavefunction going to be like for the new potential?

i'd think everything else stays the same in the wavefunction except replacing x with (x-x_o) and

w_1 with w_2?
 
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If the change is really sudden, then immediately after the change the wavefunction is going to be exactly the same as before. If you let the system evolve, then it will change to "adapt" to V2, according to the TDSE with the initial conditions being that the wavefunction at t=0 will be equal to the wavefunction corresponding to the initial potential. A process that changes very rapidly is called a diabatic process.
 

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