- #1

Sushmita

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## Homework Statement

[/B]

A particle of mass 'm' is initially in a ground state of 1- D Harmonic oscillator potential V(x) = (1/2) kx

^{2}. If the spring constant of the oscillator is suddenly doubled, then the probability of finding the particle in ground state of new potential will be?

(A) 2

^{1/4}/(1+ 2

^{1/2})

(B) 2

^{5/4}/(1+2

^{1/2})

(C) 2/(1+2

^{1/2})

(D) 2

^{3/2}/(1+2

^{1/2})

## Homework Equations

I calculated state with the wave function of one dimentional harmonic oscillator given by

Ψ = (k/πħ)

^{¼}exp

^{(-kx2/2ħ)}

When k was doubled, new wave function becomes

Ψ'= (2k/πħ)

^{¼}exp

^{(-2kx2/2ħ)}

## The Attempt at a Solution

I tried solving the question by calculating the probability by finding the inner product of the two but I cannot solve it

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