Changing the interval of integration

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SUMMARY

The discussion focuses on the integration intervals used in two methods: Green's theorem and path integration. The first method integrates over the interval [0, π] using Green's theorem, while the path integration method integrates over [0, 2π]. Participants clarify that the value of an integral remains consistent regardless of the parametrization chosen, emphasizing that the surface calculation in Stokes' theorem is performed over [0, π]. This highlights the importance of understanding the relationship between different integration techniques in vector calculus.

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  • Basic concepts of parametrization in calculus
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Amaelle
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Homework Statement
look at the image
Relevant Equations
Green theorem
Greetings Dear community!
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Here is the solutions using two different methods: the first method is the Green theorem and the second is the simple path integration method:


My question is why they integrate over [0.2pi] in the path integration method while they integrate within [0. pi] in the green method (I do agree with it)?


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thank you!
 

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They don’t seem to be using any parametrization at all when applying Stokes’ theorem.

The value of an integral does not depend on the parametrization. You could have picked a parameter taking values in ##[-200.5,\pi]## and you would get the same result (although a bit more annoying expressions for the differentials).
 
for the stock theroem they calculate the surface by integrating from [0 ,pi], this is why i don't understand why they didn't do the same for the path integral
 

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