Changing the interval of integration

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The discussion revolves around the integration intervals used in two methods: the Green theorem and path integration. The author questions why the path integration method uses the interval [0, 2π], while the Green theorem uses [0, π]. It is noted that the value of an integral remains consistent regardless of the parametrization chosen. The application of Stokes' theorem in the context of the surface calculation is highlighted, emphasizing the difference in integration limits. The conversation seeks clarity on the rationale behind the differing intervals in these integration methods.
Amaelle
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Homework Statement
look at the image
Relevant Equations
Green theorem
Greetings Dear community!
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Here is the solutions using two different methods: the first method is the Green theorem and the second is the simple path integration method:


My question is why they integrate over [0.2pi] in the path integration method while they integrate within [0. pi] in the green method (I do agree with it)?


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thank you!
 

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They don’t seem to be using any parametrization at all when applying Stokes’ theorem.

The value of an integral does not depend on the parametrization. You could have picked a parameter taking values in ##[-200.5,\pi]## and you would get the same result (although a bit more annoying expressions for the differentials).
 
for the stock theroem they calculate the surface by integrating from [0 ,pi], this is why i don't understand why they didn't do the same for the path integral
 

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