Changing the interval of integration

Amaelle
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Homework Statement
look at the image
Relevant Equations
Green theorem
Greetings Dear community!
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Here is the solutions using two different methods: the first method is the Green theorem and the second is the simple path integration method:


My question is why they integrate over [0.2pi] in the path integration method while they integrate within [0. pi] in the green method (I do agree with it)?


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thank you!
 

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They don’t seem to be using any parametrization at all when applying Stokes’ theorem.

The value of an integral does not depend on the parametrization. You could have picked a parameter taking values in ##[-200.5,\pi]## and you would get the same result (although a bit more annoying expressions for the differentials).
 
for the stock theroem they calculate the surface by integrating from [0 ,pi], this is why i don't understand why they didn't do the same for the path integral
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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