Charge density in cylinder with uniform charge

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SUMMARY

The discussion centers on calculating the electric field inside a uniformly charged non-conducting cylinder using Gauss's Law. The charge density ρ is uniformly distributed throughout the cylinder of radius R. The correct formula for the electric field at a distance r = R/2 from the cylinder's axis is E = ρR/4ε0, which differs from the incorrect calculation of E = ρ/4ε0 presented by the user. The error arises from a misunderstanding of the relationship between volume and surface area in the application of Gauss's Law.

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1. A charge density ρ (charge per unit volume) is distributed uniformly throughout a non-conducting cylinder of radius R. What is the magnitude of the electric field a distance r = R/2 from the cylinder's axis?

Homework Equations



E ∫dA = q(interior)/ε0[/B]3.

So I tried doing EA = (ρA)(v/V)/ε0 where v is the volume of the Gaussian surface and V is the volume of the cylinder

E = (ρ*(πR^2L/4πR^2L))/ε0
E = ρ/4ε0

However the answer is supposed to be E = ρR/4ε0

I'm not sure where I'm going wrong
 
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Check Gauss law once more: one is a volume (to determine q(interior) ) and the other is an area (of the surface).
 

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