Charge enclosed in uniform electric field

[yeahhyeahyeah]

1b]1. Homework Statement

A cube oriented so that its corner lies on the origin and it extends positive 1m in the x, y, and z direction. An electric field of 3.00 i + 2.5 j passes through this space. What is the charge enclosed by the cube?

The Attempt at a Solution

Gauss' law is
integr(E . dA) = Q/epsilon

since the surface is of a cube, you can add the dot product of E and dA for every face except for the one lying in the x-y plane because there is no 'k' component of the E field.
The dot products of the faces cancel out though
So the the total charge enclosed is 0
is that right?

 

[LowlyPion]

If the electric field is uniform across the space the cube is in, then you are right that there is no charge inside, because for there to be a charge inside there would have to be a net non-zero flux through all of the faces of the cube.