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**1b]1. Homework Statement**

A cube oriented so that its corner lies on the origin and it extends positive 1m in the x, y, and z direction. An electric field of 3.00 i + 2.5 j passes through this space. What is the charge enclosed by the cube?

## The Attempt at a Solution

Gauss' law is

integr(E . dA) = Q/epsilon

since the surface is of a cube, you can add the dot product of E and dA for every face except for the one lying in the x-y plane because there is no 'k' component of the E field.

The dot products of the faces cancel out though

So the the total charge enclosed is 0

is that right?