Charge on 6.0-μF Capacitor at 40V: 240microC

  • Thread starter Thread starter Curious314
  • Start date Start date
  • Tags Tags
    Capacitor Charge
Click For Summary
SUMMARY

The charge on a 6.0-μF capacitor charged to 40V is calculated using the formula q = CV. Substituting the values, q = (6μF) * (40V) results in a charge of 240μC. This calculation is confirmed as correct by multiple participants in the discussion.

PREREQUISITES
  • Understanding of capacitor basics
  • Familiarity with the formula q = CV
  • Knowledge of microfarads (μF) as a unit of capacitance
  • Basic electrical concepts such as voltage (V)
NEXT STEPS
  • Review the principles of capacitance and how capacitors store charge
  • Explore the effects of varying voltage on capacitor charge
  • Learn about different capacitor types and their applications
  • Study series and parallel capacitor configurations
USEFUL FOR

Students studying electrical engineering, electronics enthusiasts, and anyone looking to understand capacitor behavior in circuits.

Curious314
Messages
31
Reaction score
0

Homework Statement


What charge appears on the plates of a 6.0-μF capacitor when it is charged to 40 V?


Homework Equations



q=CV

The Attempt at a Solution



q= CV
q=(6microF)*(40V)
q=240microC

am I right here??

thanks!
 
Physics news on Phys.org


Curious314 said:

The Attempt at a Solution



q= CV
q=(6microF)*(40V)
q=240microC

am I right here??

thanks!

Yep! That's correct! :smile:
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 8 ·
Replies
8
Views
7K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K