1. The problem statement, all variables and given/known data The circuit has been completed for several minutes. Suppose that ε = 55 V . Calculate the magnitude of charge on the 100 μF capacitor plate. 2. Relevant equations Q = C * V 3. The attempt at a solution Since the capacitors have been fully charged, current has stopped flowing at the 300 Ω and 100 Ω resistors. But for the other resistors, current still flows by the junction and loop rules. So, Q = 100 μF * 55 V = .0055 C. But that is wrong, and I do not understand. If the capacitor is already fully charged, does that not mean it equals the voltage of the battery? Why am I not getting the right answer?