- #1

AnonBae

- 8

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## Homework Statement

The circuit has been completed for several minutes. Suppose that ε = 55 V .

Calculate the magnitude of charge on the 100 μF capacitor plate.

## Homework Equations

Q = C * V

## The Attempt at a Solution

Since the capacitors have been fully charged, current has stopped flowing at the 300 Ω and 100 Ω resistors. But for the other resistors, current still flows by the junction and loop rules. So, Q = 100 μF * 55 V = .0055 C.

But that is wrong, and I do not understand. If the capacitor is already fully charged, does that not mean it equals the voltage of the battery? Why am I not getting the right answer?