Charge on a capacitor in a series

  • #1

Homework Statement



103szyq.png

[/B]
A circuit is constructed with five capacitors and a battery as shown. The values for the capacitors are: C1 = C5 = 3.9 μF, C2 = 3.9 μF, C3 = 5.7 μF, and C4 = 4.2 μF. The battery voltage is V = 12 V.

What is Q5, the charge on capacitor C5?

Homework Equations


C=Q/V

The Attempt at a Solution


Okay, I thought that voltage across series capacitors was all the same across each one. Treating the parallel system as one capacitor of equivalent capacitance, I thought you could just divide the voltage by 3, and then multiply by C5 to get the charge on C5. I tried this and the answer is wrong. I'm really confused.
 

Answers and Replies

  • #2
ehild
Homework Helper
15,543
1,915

Homework Statement



103szyq.png

[/B]
A circuit is constructed with five capacitors and a battery as shown. The values for the capacitors are: C1 = C5 = 3.9 μF, C2 = 3.9 μF, C3 = 5.7 μF, and C4 = 4.2 μF. The battery voltage is V = 12 V.

What is Q5, the charge on capacitor C5?

Homework Equations


C=Q/V

The Attempt at a Solution


Okay, I thought that voltage across series capacitors was all the same across each one. Treating the parallel system as one capacitor of equivalent capacitance, I thought you could just divide the voltage by 3, and then multiply by C5 to get the charge on C5. I tried this and the answer is wrong. I'm really confused.

The voltage across capacitors in series is not the same, unless the capacitances are equal. What is the resultant of C2, C3 and C4? Is it equal to 3.9 μF?
I think you mix charge with voltage. The charge is same on series capacitors .
 

Related Threads on Charge on a capacitor in a series

Replies
5
Views
2K
Replies
1
Views
44K
S
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
5
Views
574
  • Last Post
Replies
15
Views
630
Replies
3
Views
6K
  • Last Post
Replies
2
Views
627
  • Last Post
Replies
11
Views
2K
Replies
5
Views
1K
Replies
3
Views
3K
Top