Charge On A Infinite Conductor Slab From An Infinite Sheet Of Charge

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SUMMARY

The discussion centers on calculating the charge per unit area on the surface of an infinite conductor slab positioned between an infinite sheet of charge and its own surface charge. The infinite sheet has a charge density of σ = -2.1 μC/m², while the conductor slab has a charge density of σ = 74 μC/m². The correct charge density at the outer edge of the slab, located 4.2 cm away, is determined to be 71.9 μC/m², although this was initially miscalculated. The resolution involves applying Gauss's Law and considering the contributions of the electric fields from both the infinite sheet and the conductor itself.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with charge density concepts (e.g., micro-coulombs per square meter)
  • Knowledge of electric fields generated by infinite sheets of charge
  • Basic principles of conductors in electrostatic equilibrium
NEXT STEPS
  • Study the application of Gauss's Law in different geometries
  • Learn about electric field calculations for multiple sheets of charge
  • Explore the concept of electrostatic shielding in conductors
  • Investigate the effects of charge distribution on conductors in electrostatic equilibrium
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or conducting materials will benefit from this discussion.

Baumer8993
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Homework Statement



http://imgur.com/sg8czUR

An infinite sheet of charge has a charge density of σ= -2.1 uc/m2. (uc is micro-coulombs). The inner edge of the infinite conductor slab is 2.6 cm away. The outer edge is 4.2 cm away. The conductor slab has a charge density of σ= 74 uc/m2. What is the charge per unit area on the surface of the slab at 4.2 cm. (The outer edge)

Homework Equations



Gauss's Law!

The Attempt at a Solution



Well we know since the slab is a conductor the charges in it are going to move to make the electric field equal zero every inside of it. I have the inner being 2.1 uc/m2. The total charge of the slab must be 74 uc/m2. Therefore I thought the outer edge will have a charge of 71.9 uc/m2. But this is not the right answer. Any idea of what I am doing wrong here?
 
Last edited:
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If you have 2.1 μC on the left surface of the conductor, the electric fields due to that charge and the sheet of charge will indeed cancel inside the conductor, but you would still have the rest on the charge on the conductor around, which would result in a non-zero field inside the conductor.

Look at it as three sheets of charge: the one through the origin, the one on the left surface of the conductor, and the one on the right surface of the conductor. The fields from the three sheets have to sum to zero inside the conductor.
 
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