Charge & Spin Ordering: Explained & Bond Lengths

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SUMMARY

This discussion clarifies the concepts of charge and spin ordering, highlighting that charge order is homogeneous while spin order can be complex, as illustrated by Holmium metal's helicomagnetic behavior. It establishes that higher oxidation states, such as Te4+ compared to Te5+, typically result in shorter bond lengths due to increased Coulomb interactions, although bond length equality can vary based on bonding specifics and phenomena like Jahn-Teller distortion. Additionally, it explains the magnetic properties of niobium, noting that Nb5+ is diamagnetic due to a d0 configuration, while Nb4+ is paramagnetic with a d1 configuration.

PREREQUISITES
  • Understanding of charge and spin ordering in solid-state physics
  • Familiarity with oxidation states and their effects on bond lengths
  • Knowledge of Jahn-Teller distortion and its implications
  • Basic principles of magnetism, particularly in transition metals
NEXT STEPS
  • Research the effects of Jahn-Teller distortion on molecular geometry
  • Study the magnetic properties of transition metals and their oxidation states
  • Explore the concept of helicomagnetism and its applications
  • Learn about Nilsson diagrams for calculating ground state spins in nuclei
USEFUL FOR

Chemists, physicists, and materials scientists interested in solid-state properties, transition metal chemistry, and magnetic materials will benefit from this discussion.

marie2010
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hi,
Can someone explain to me the difference between charge and spin ordering? How are they different and how are they related? I am very confused.
Also, how are the bond lengths affected if an element is in 4+ as opposed to 5+ (e.g. Te4+ or Te5+ bonded to 6 oxygens). Are they shorter/longer, unequal distribution.
Can someone please comment.
Thanks.
 
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Maybe an example is helpful: E. g. Holmium metal is a helicomagnet. Although the charge density at each Holmium atom is equal, the spin of the electrons at different sites points in different directions. Specifically, when moving along some axis in the crystal the spin rotates tracing out a helix in space. So while charge order is homogeneous, the spin order is quite complex.
To the second question: Typically, the higher the charge of the central atom, the shorter the bonds (due to the increased Coulomb interaction). Whether the bond length become unequal depends on details in the bonding and cannot be answered generally. A common cause for unequal bond length is a Jahn Teller distortion.
 
how to calculate ground state spins of odd-odd nucleus in the nilsson diagrams
 
Thank you for replying. Can you please help me understand the following:
How come Nb5+ is d0 and diamagnetic, but Nb4+ is d1. I cannot see it.
Thanks in advance.
 
Niob is in the fifth secondary group in the periodic system, i.e. it has 5 valence electrons (3 d- electrons and 2 s electrons). In Nb(V) you removed all of them leaving only filled shells, hence it is diamagnetic. In Nb(IV) one d-electron is left. Hence it is paramagnetic.
 
Thank you. I got it now.
 

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