Charge through lightbulb(just needs checked)

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SUMMARY

The discussion centers on calculating the charge passing through an 80-watt light bulb with a current of 0.5A over a duration of 1 hour. The relevant equation used is i = Q/T, which can be rearranged to Q = i * T. The wattage is deemed irrelevant for this calculation since the current and time are sufficient to determine the charge. The resistance of the light bulb is calculated to be 320 ohms, although this information is not necessary for the charge calculation.

PREREQUISITES
  • Understanding of basic electrical concepts such as current, charge, and time.
  • Familiarity with the formula i = Q/T for calculating charge.
  • Knowledge of electrical units, specifically amperes (A) and coulombs (C).
  • Basic understanding of resistance and its relationship to voltage and current (Ohm's Law).
NEXT STEPS
  • Study the relationship between power, current, and resistance using the formula P = IV.
  • Learn how to calculate charge in different scenarios involving varying currents and times.
  • Explore the implications of resistance in electrical circuits and how it affects current flow.
  • Investigate the concept of energy consumption in electrical devices, particularly in relation to wattage.
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Students studying physics or electrical engineering, educators teaching basic electrical concepts, and anyone interested in understanding charge calculations in electrical circuits.

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Homework Statement


An 80 watt light bulb has a current of .5A running through it. What is the charge through the lightbulb after 1 hour?


Homework Equations


i=Q/T


The Attempt at a Solution


For this question is the wattage irrelevant because we know current and time?

We would just use i*T=Q?
 
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Yeah, I don't know why it gives you the wattage. You can get the the resistance is 320 just for fun. :p
 

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