Charged Aluminum Spheres: Determining Number of Electrons

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SUMMARY

The discussion focuses on calculating the number of electrons in two charged aluminum spheres, each weighing 0.0250 kilograms and separated by 80.0 centimeters. The atomic mass of aluminum is 26.982 grams per mole, and its atomic number is 13, indicating that each aluminum atom contains 13 electrons. The solution involves converting the mass of the spheres to grams, calculating the number of moles, and then determining the total number of electrons by multiplying the moles by the number of electrons per atom. The final calculation confirms that each sphere contains approximately 12.0 electrons per atom, leading to a total of 12 electrons per sphere.

PREREQUISITES
  • Understanding of atomic structure and electron configuration
  • Basic knowledge of moles and molar mass calculations
  • Familiarity with unit conversions (grams to kilograms)
  • Knowledge of fundamental chemistry equations related to moles
NEXT STEPS
  • Study the concept of moles and molar mass in detail
  • Learn about atomic structure and electron distribution in elements
  • Explore the principles of electrostatics and charge interactions
  • Investigate the properties of aluminum and its applications in electronics
USEFUL FOR

This discussion is beneficial for students in chemistry and physics, educators teaching atomic theory, and anyone interested in the properties of materials and their electrical characteristics.

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[SOLVED] Charged Aluminum Spheres

Homework Statement


Two small aluminum spheres, each of mass 0.0250 kilograms, are separated by 80.0 centimeters.

How many electrons does each sphere contain? (The atomic mass of aluminum is 26.982 grams per mole, and its atomic number is 13.)

Homework Equations


Conversions from a chemistry course so long ago...

The Attempt at a Solution


.0250 kg * (1000g/1kg) = 25.0 g * (1 mole/26.982g) = .927 mole * (13 e- / mol) = 12 e-
 
Physics news on Phys.org
13 electrons/atom... not 13 electrons/mole.
 
Nevermind, figured it out. ;)
 
Last edited:

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