Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Advanced Physics Homework Help
Charged conducting sphere in a uniform electric field?
Reply to thread
Message
[QUOTE="kuruman, post: 6648032, member: 192687"] You shouldn't be happy. You can no longer consider the potential on the sphere zero because it has charge Q which raises the potential of the conductor to ##V_0=\frac{Q}{4 \pi \epsilon_0 R}##. It also raises the potential every where outside the sphere by adding an additional ##1/r## term. Thus, the new potential outside the sphere is the old potential plus the potential of point charge ##Q## placed at the center of the sphere. This new potential is a solution to Laplace's equation and satisfies the boundary conditions. Therefore, by the uniqueness theorem is [B]the[/B] solution. [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Advanced Physics Homework Help
Charged conducting sphere in a uniform electric field?
Back
Top