Charged particle in a magnetic field

  • Thread starter Nivlac2425
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  • #1
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Homework Statement


A charged particle with a charge-to-mass ratio of 5.7 x 10^8 C/kg travels on a circular path that is perpendicular to a magnetic field whose strength is .72 T.
How much time does it take for the particle to make one revolution?


Homework Equations


(Magnetic)F = qvB = (Centripetal)F = (mv^2)/r


The Attempt at a Solution


I can produce an equation for the velocity of the particle using the above equation, but how would one find the time that it takes? Hmmm, I know this is probably right in front of my face, but I'm just not seeing it.... time...hmm...any hints?

Thank you everyone for even trying to help me out! :biggrin:
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
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v = ω*r = (2*π /T)*r
 
  • #3
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Hahaha! Oh, how did I not think of that! Such a fundamental idea didn't cross my mind!
Thank you for helping out, I'll have to think clearly next time!

:approve:
 

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