A charged particle with a charge-to-mass ratio of 5.7 x 10^8 C/kg travels on a circular path that is perpendicular to a magnetic field whose strength is .72 T.
How much time does it take for the particle to make one revolution?
(Magnetic)F = qvB = (Centripetal)F = (mv^2)/r
The Attempt at a Solution
I can produce an equation for the velocity of the particle using the above equation, but how would one find the time that it takes? Hmmm, I know this is probably right in front of my face, but I'm just not seeing it.... time...hmm...any hints?
Thank you everyone for even trying to help me out!