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Charged particle in a magnetic field

  1. Feb 17, 2009 #1
    1. The problem statement, all variables and given/known data
    A charged particle with a charge-to-mass ratio of 5.7 x 10^8 C/kg travels on a circular path that is perpendicular to a magnetic field whose strength is .72 T.
    How much time does it take for the particle to make one revolution?

    2. Relevant equations
    (Magnetic)F = qvB = (Centripetal)F = (mv^2)/r

    3. The attempt at a solution
    I can produce an equation for the velocity of the particle using the above equation, but how would one find the time that it takes? Hmmm, I know this is probably right in front of my face, but I'm just not seeing it.... time...hmm...any hints?

    Thank you everyone for even trying to help me out! :biggrin:
  2. jcsd
  3. Feb 17, 2009 #2


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    Homework Helper

    v = ω*r = (2*π /T)*r
  4. Feb 18, 2009 #3
    Hahaha! Oh, how did I not think of that! Such a fundamental idea didn't cross my mind!
    Thank you for helping out, I'll have to think clearly next time!

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