Charges on a square - find forces

[moondawg]

Homework Statement

A charge of 6 mC is placed at each corner of a square .1 m on each side. Determine the magnitude and driection of the force.

Homework Equations

The Attempt at a Solution

so i found the force between corner 1 and 2 then 1 and 3 to = 32.4N and the force between corner 1 and 4( the corner diagonal to the top left corner) to be 16.2. Then i set up my vectors and found an imaginary hypotenuse and added it to the 16.2 to get 62.02 as my final answer. I'm pretty sure i did it correctly but i only found the magnitude how do i find the direction? I have not a clue. HELP!? pleasezzzzzzzzzzzzzzzzzzzzzz

 

[SammyS]

Homework Statement

A charge of 6 mC is placed at each corner of a square .1 m on each side. Determine the magnitude and direction of the force.

I have not a clue. HELP!? pleasezzzzzzzzzzzzzzzzzzzzzz

Find the force exerted upon what object?

Are there any coordinate axes?

 

[gneill]

Homework Statement

A charge of 6 mC is placed at each corner of a square .1 m on each side. Determine the magnitude and driection of the force.

Is that mC a milliCoulomb or a microCoulomb?

The Attempt at a Solution

so i found the force between corner 1 and 2 then 1 and 3 to = 32.4N and the force between corner 1 and 4( the corner diagonal to the top left corner) to be 16.2. Then i set up my vectors and found an imaginary hypotenuse and added it to the 16.2 to get 62.02 as my final answer. I'm pretty sure i did it correctly but i only found the magnitude how do i find the direction? I have not a clue. HELP!? pleasezzzzzzzzzzzzzzzzzzzzzz

What are the units of your answer?

Take a look at each of the individual forces that you calculated. They have magnitude and direction. That suggests vectors. How do you add vectors to fins a resultant?

 

[moondawg]

Because all of the forces were repelling i put 1 vector up, one vector perpendicular starting its right end at the tip of the first vector and my last vector connected to my 2nd vector and going in a diagonal northwest direction. then i found the hypotenuse between the 1st and 2nd vector and added that hypotenuse to the length of my 3rd vector and my units are in meters... i know i basically restated what i just said i just wanted to better explain my process bc I am not sure if it is correct..