Charges placed in right triangle pls HELP

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To find the electrical field strength at point "A," located at the midpoint of the hypotenuse in a right triangle with charges q1, q2, and q3, start by applying the equation E = kq/r^2 for each charge. Since point A is equidistant from the triangle's vertices, calculate the electric fields produced by q1 and q2, noting they will act in opposite directions. Determine the resultant of these two fields, then find the angle between this resultant and the field from charge q3. Finally, combine all three fields to find the overall electric field strength and direction at point A. Understanding vector addition is crucial for this calculation.
sunny.heyar
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Homework Statement


Charges q1, q2, q3 are placed in a right triangle.
Charges are given, distance between charges is given.
Find the electrical field strength at point "A" which is in the middle of the hypotenuse.
Which equations and how would I figure that out knowing that I have to give magnitude and direction?

Homework Equations


E=kq/r^2 --> ?not sure


The Attempt at a Solution


I drew out a diagram and found all the angle, after that I am completely lost.
 
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In a right angled triangle, mid point of the hypotenuse is equidistant from three vertexes.
At A, two fields are in the opposite direction due to two charges at the ends of the hypotenuse. Find the resultant of these two. You can find the angle between the resultant of the two field and third field,and resultant of all the three fields.
 

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