Hi guys,(adsbygoogle = window.adsbygoogle || []).push({});

I've been reading the forums and finally I have something to post

I've got a question regarding charging parallel plate capacitors. Take this for example:

Connect a 6 Volt power supply to a resistor of 2Mohm and in series with a 15uF capacitor initially uncharged, with a current of 0.0000018A flowing through.

A simple calculation would show that the P.D across the capacitor is 2.4V. The question then goes on to ask what is the new p.d across the capacitor when it is fully charged and reduced to 5uF without any loss of charges and the answer is 16.8V

I figured in order to get the answer the charges in the capacitor must be that of 6V x 15uF. My question is that how then would the capacitor gets charged up to the maximum of 6V (how would one know the max is 6V?) with the presence of the resistor?

I can't really grasp the concept here hope someone can help me out with the explanation and sorry for being so long winded cant find an easier way to put it across!

Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Charging a parallel plate capacitor

**Physics Forums | Science Articles, Homework Help, Discussion**