Check if the function is odd or even

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    even Function
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Homework Help Overview

The discussion revolves around determining whether a given function is odd or even, specifically focusing on the properties of functions and their behavior under transformations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the definitions of odd and even functions but encounters difficulties with specific cases. Some participants suggest examining the behavior of the function more closely, particularly through transformations and logarithmic properties.

Discussion Status

Participants are exploring the definitions and characteristics of odd and even functions, with some guidance provided on analyzing specific cases. There is an acknowledgment that many functions do not fit neatly into these categories.

Contextual Notes

The original poster references a specific case that is not yielding the expected results, indicating potential confusion or missing information regarding the function's behavior.

transgalactic
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i know that if f(x)=f(-x) and if f(-x)=-f(x) then its odd.

i tried to do this check on this cases
but its not working

http://img126.imageshack.us/img126/3942/74448798fv8.gif
 
Last edited by a moderator:
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These questions aren't always straight forward, you need to understand how the functions behave. Let's consider the first case:

So you have

[tex]f\left(-x\right) = \log\left(\frac{1+x}{1-x}\right) = \log\left(\frac{1-x}{1+x}\right)^{-1} = - \log\left(\frac{1-x}{1+x}\right) = -f\left(x\right)[/tex]

Do you follow?
 
And, of course, most functions are neither even nor odd.
 
thanks
 

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