Check Max Speed of Car on Circular Path Without Skidding

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SUMMARY

The maximum speed at which a car can travel around a circular path without skidding is determined by the radius of the path and the coefficient of static friction. In this discussion, a car with a radius of 20.0 m and a static friction coefficient of 0.72 was analyzed. The correct maximum speed, calculated using the formula v = sqrt(μ * g * r), is 12 m/s, not 18 m/s as initially suggested. This conclusion is based on the assumption of gravitational acceleration (g) being 10 m/s².

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  • Understanding of circular motion dynamics
  • Knowledge of static friction coefficients
  • Familiarity with basic physics equations, particularly v = sqrt(μ * g * r)
  • Ability to perform unit conversions and calculations
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  • Study the physics of circular motion and centripetal force
  • Learn about the role of friction in vehicle dynamics
  • Explore the implications of varying coefficients of friction on vehicle performance
  • Investigate real-world applications of these principles in automotive engineering
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nelone
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Check a physics "Q".

For this question i got 18m/s is this correct?
A car travels in a circular path of radius 20.0 m. If the coefficient of static friction is 0.72, find the maximum speed at which the car can travel around the curve without skidding. Assuming g=10m/s^2.
 
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I think not.

How did you get this ?
 
Figured it out!

Gokul43201 said:
I think not.

How did you get this ?
The correct answer is 12m/s thanks for replying.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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