Check my answer for implicit function problem?

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Homework Help Overview

The discussion revolves around using the Implicit Function Theorem to find the derivative dy/dx at the point (1,1) for the equation y^5 + x^2*y^3 − y*e^(x^2) = 1. Participants are exploring the application of the theorem rather than implicit differentiation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss their attempts to derive dy/dx using the Implicit Function Theorem, with one participant expressing confusion about the differentiation of the term involving e^(x^2). There are inquiries about the correctness of the equations derived for dy/dx and the specific terms involved in the differentiation process.

Discussion Status

There is a mix of results reported by participants, with one stating dy/dx as 0.65 and another as -1.41. Some participants are checking each other's work and clarifying their differentiation steps, indicating an ongoing exploration of the problem without a clear consensus on the correct answer.

Contextual Notes

Participants are working under the constraint of using the Implicit Function Theorem specifically, rather than implicit differentiation, which may influence their approaches and understanding of the problem.

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Homework Statement


Use the IMPLICIT FUNCTION THEOREM (and not implicit differentiation) to find dy/dx at the point (1,1) when
y^5 + x^2*y^3 − y*e^(x^2) = 1.

Homework Equations


f(x,y)=0
dy/dx = - [f(x)/f(y)] = -[d/dx(f(x,y) / d/dy(f(x,y)]

The Attempt at a Solution


solving for f(x,y), i brought the 1 to the left side so the equation equaled 0, i.e y^5 + x^2*y^3 − y*e^(x^2)-1=0

then d/dx of the function I got 2xy^3 - 2xye^(x^2)
d/dy = 5y^4 + 3x^2y^2 - e^(x^2)

so dy/dx was just -[d/dx / d/dy] = -[2xy^3 - 2xye^(x^2) / 5y^4 + 3x^2y^2 - e^(x^2)]
for the point (1,1) i just plugged in x and y into the above equation, and got 0.65 as my answer.
 
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I got:

dy/dx = -1.41
 
can you show your work? did you get the same equation for dy/dx as me? if i got mine wrong it was probably the ye^(x^2) part, since i was kinda confused how to work it. for d/dx, i got 2xye^(x^2), and for d/dy i got e^(x^2).
 
sorry, my mistake, I also got

dy/dx = 0,65
 

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