Checking a commutation relation for angular momentum and lin. momentum

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SUMMARY

The discussion focuses on proving the commutation relation \(\left [L_x, p_y \right] = i\hbar \epsilon_{xyz} p_z\) in quantum mechanics. The relevant equations include \(L_x = yp_z - zp_y\) and \(p_z = i\hbar \frac{\partial}{\partial z}\). The user attempts to simplify the expression but encounters difficulties with remaining derivatives of \(y\). The solution emphasizes the importance of applying the product rule when taking derivatives to resolve the issue.

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  • Understanding of quantum mechanics, specifically angular momentum operators.
  • Familiarity with commutation relations in quantum mechanics.
  • Knowledge of partial derivatives and their applications in physics.
  • Proficiency in using the product rule for differentiation.
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  • Study the derivation of commutation relations in quantum mechanics.
  • Learn about the product rule in calculus and its implications in physics.
  • Explore angular momentum operators in quantum mechanics, focusing on \(L_x\) and \(p_y\).
  • Investigate the Levi-Civita symbol \(\epsilon_{xyz}\) and its role in vector calculus.
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tomwilliam2
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Homework Statement



Prove the commutation relation ##\left [L_x, p_y \right] = i\hbar \epsilon_{xyz} p_z##

Homework Equations


##L_x = yp_z - zp_y##
##p_z = i\hbar \frac{\partial}{\partial z}##

The Attempt at a Solution



##\left [L_x, p_y \right] = (yp_z - zp_y)p_y - p_y(yp_z - zp_y)##
##\left [L_x, p_y \right] = \left (y\cdot i\hbar \frac{\partial}{\partial z}\cdot i\hbar \frac{\partial}{\partial y} - z\cdot i\hbar \frac{\partial}{\partial y}\cdot i\hbar \frac{\partial}{\partial y}\right ) -\left ( i\hbar \frac{\partial y}{\partial y}i\hbar \frac{\partial}{\partial z} - i\hbar \frac{\partial z}{\partial y} i\hbar \frac{\partial}{\partial y} \right )##
##\left [L_x, p_y \right] = -y\hbar^2 \frac{\partial^2}{\partial z \partial y} + z\hbar^2 \frac{\partial^2}{\partial y} + \hbar^2\frac{\partial^2}{\partial z^2}##

I don't see how I can turn this into the final answer, given that I have derivatives of y still left...so where did I go wrong?
Thanks in advance
 
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You need to remember to use the product rule when taking derivatives.
 
Thanks! That old mistake...
 

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