Checking Algebra Homework Solutions

Click For Summary

Homework Help Overview

The discussion revolves around checking solutions to algebra homework problems, including solving equations, evaluating functions, and determining domains. The original poster presents several algebraic expressions and their evaluations, seeking confirmation of their correctness.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to solve an equation involving fractions and checks the correctness of function evaluations and domain determination. Some participants question the clarity of the expressions presented, particularly regarding the placement of variables in the fractions and the interpretation of the domain for the function g(x).

Discussion Status

Participants are actively engaging with the original poster's attempts, providing feedback on specific evaluations and questioning assumptions about the expressions. There is no explicit consensus, but some guidance has been offered regarding the interpretation of the domain and the need for clarity in notation.

Contextual Notes

There is uncertainty regarding the correct interpretation of the function g(x) due to potential typographical errors in the original poster's expressions. Additionally, the original poster expresses confusion about their evaluations and seeks further validation of their answers.

1babelove
Messages
4
Reaction score
0

Homework Statement


5/8x + 1/16x= 9/16 + x


Homework Equations





The Attempt at a Solution


10x+ x = 9+16
11x=9+16x
-5x=9
x= - 9/5
x =- 1.8

Is this correct. I am trying to make sure I am in the right direction


Also is f(x) = 2x^2-2x
f(0) = I got )
f(-1) I got 4
f(2) Igot 4

Is this correct also..

I need to make sure that this one is correct also

What is the domain of g(x) = 3/5-3x
I got that x is not equal to 5/3.

I hope I got all these right...
 
Physics news on Phys.org
I think you have a typo for f(0), what did you get? I agree with your answer for f(-1) and f(2). If part 1 has the x upstairs in the fractions like,
(5*x)/8 + (1*x)/16 = 9/16 + x
then I agree with your answer. But not if it is downstairs like,
5/(8*x) +1/(16*x) = 9/16 +x

I'm not sure I agree with your domain of g(x). What is your reasoning for 5/3?
 
Because I can not see g(x) = 3/5-3x answers being either a.not equal to 3, b. equal to 0. or c x greater than or equal to 5/3..My head is spinning numbers maybe I am wrong

and for f(0) = 2x^2 -2x when you mutiply be zero the answer is 0..right?
 
The problem with the domain question is that we were not sure if you meant
g(x) = \frac{3}{5 - 3x}
or
g(x) = \frac{3}{5} - 3x.

It looks like you meant the former. (That is why it's helpful to learn LaTex. :wink:) Anyway, you're right -- the domain is
x \neq \frac{5}{3}.


01
 
I have a some more problems that I want checked will you be willing to look at them, please.
 
Just post them in a new thread. Also, if you're seriously unsure whether your answer is correct or not, point out which steps you weren't sure about when you were solving the question.
 

Similar threads

Replies
5
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
3K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 105 ·
4
Replies
105
Views
8K