Checking Voltage Drop while Supplying 6A Current

[mares0909]

Homework Statement

You would like to check if the battery voltage drops while it is supplying a current of 6A. You use a voltmeter designed to measure voltages up to 20V and having a resistance of 50,000 Ohms.
See attachment****

This connection is in series so V= I (R1+R2)
V / (R1+R2) = I
12 / (2+ 50000) = I
2.39E-4 = I

How much current (in A) would flow through the headlight for Circuit b?

The connection is in parallel so Req = (1/ R1 + 1/R2)
Req = (1/2 + 1/50000) = .50002

I = V / R
I = 12 / .50002
I= 23.99

Homework Equations

I want to check if what I have done is right.

The Attempt at a Solution

Is right bellow the questions.

Thanks

 

[montoyas7940]

You have your formula for Req wrong.

It should be 1/Req= (1/R1 + 1/R2)

So, Req = 1.99992.