Chemistry - calculating equilibrium constant, what am I doing wrong?

Click For Summary
SUMMARY

The discussion centers on calculating the equilibrium constant (K) for the decomposition of dinitrogentetraoxide (N2O4) into nitrogen dioxide (NO2) at 373 K. The initial concentration of N2O4 is 0.400 mol in a 1.00-L flask, with 0.0055 mol remaining at equilibrium. The correct calculation reveals that 0.789 mol of NO2 is produced, leading to an equilibrium constant of K = 113, which was misrepresented in the original answer choices. Participants emphasize the importance of correctly applying stoichiometry in equilibrium calculations.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Knowledge of stoichiometry and mole calculations
  • Familiarity with the equilibrium constant expression
  • Basic grasp of gas laws and behavior at different temperatures
NEXT STEPS
  • Study the derivation of the equilibrium constant expression for reactions
  • Practice stoichiometric calculations involving gas reactions
  • Learn about the impact of temperature on equilibrium constants
  • Explore common pitfalls in equilibrium calculations and how to avoid them
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical research or laboratory work focusing on reaction dynamics and equilibrium analysis.

confusedbyphysics
Messages
61
Reaction score
0
I feel like I know what I'm doing but I'm not getting an answer that is offered. Heres the question:

Dinitrogentetraoxide partially decomposes according to the following equilibrium:

N2O4 (g) ---> 2NO2 (g) (an arrow going other way too)


A 1.00-L flask is charged with .400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Equil. constant for this reaction is __________.

a. 2.2 x 10^-4
b. 13
c. 0.22
d. 0.022
e. 0.87K = [NO2]^2 / [N204]

N2O4 goes from .4 to .0055 mol, so that is a change of .3945 mol, which must be the equilibrium amount of the 2NO2. Since the volume is just 1 L

K = [.3945 M]^2 / [.0055 M] = 28.3

but this is not one of the choices.

what am I doing wrong?
 
Last edited:
Physics news on Phys.org
First thing you're "doing wrong" is attempting to reproduce the errors in the instructional software; you already came up with an answer of one hundred something, didn't you. You wouldn't be stating, "... .3945 mol, which must be the equilibrium amount of the 2NO2," otherwise.

If you know what you're doing, it's your call how you handle it; try to reproduce the software errors (and not rock the boat), or present your work to the instructor (or go to the department head) and get a few TAs into trouble.
 
confusedbyphysics said:
I feel like I know what I'm doing but I'm not getting an answer that is offered. Heres the question:

Dinitrogentetraoxide partially decomposes according to the following equilibrium:

N2O4 (g) ---> 2NO2 (g) (an arrow going other way too)


A 1.00-L flask is charged with .400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Equil. constant for this reaction is __________.

a. 2.2 x 10^-4
b. 13
c. 0.22
d. 0.022
e. 0.87K = [NO2]^2 / [N204]

N2O4 goes from .4 to .0055 mol, so that is a change of .3945 mol, which must be the equilibrium amount of the 2NO2.
No, there is no law of conservation of moles !

If you use up 1 mol of N2O4, you make 2 moles of NO2. In any case, the correct answer still does not exist in the provided list. Have you copied the question correctly ? Or have you mistyped choice (b) ?
 
Hi, yes the answers are exactly as my WEBCT has them.

I understand where I was messing up on the moles, but now I have an answer of 113!

Relate the change
.3945 mol N2O4/L (2 mol NO2/1 mol N2O4) = .789 mol NO2/L

0+.789 = .789 for the NO2 so [.789]^2/[.0055] = 113

is that the answer that should be correct? the 13 was just typed in incorrectly and should have been put in as 113 into webct??
 
confusedbyphysics said:
is that the answer that should be correct? the 13 was just typed in incorrectly and should have been put in as 113 into webct??
Yes, that would be my guess. Take this to your TA or instructor.
 
Equilibrium constant Help!

How do we calculate equilibrium constant if we do not know what the concentration is and all else is given in the formula?
 
Please elaborate (and don't hijack the threads).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
33
Views
19K
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
8K
Replies
1
Views
8K