Calculate Mass Percent: HNO3 in Sample

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SUMMARY

The discussion focuses on calculating the mass percent of HNO3 in a sample containing both HCl and HNO3. The sample has a density of 1.083 g/ml, and titration results show that 43.00 ml of the sample requires 29.09 ml of 0.2828 M NaOH and 7.88 ml of 0.1505 M AgNO3. The molar mass of HNO3 is specified as 63.018 g/mol. The solution involves determining the total moles of acid present through stoichiometric calculations based on the titration data.

PREREQUISITES
  • Understanding of acid-base titration principles
  • Knowledge of stoichiometry and molarity calculations
  • Familiarity with chemical reaction equations
  • Basic skills in density and mass percent calculations
NEXT STEPS
  • Learn how to perform titration calculations using molarity and volume
  • Study the stoichiometry of acid-base reactions
  • Explore the concept of mass percent and its calculation
  • Review the chemical equations for reactions involving HCl and HNO3
USEFUL FOR

Chemistry students, educators, and anyone involved in analytical chemistry or titration experiments will benefit from this discussion.

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Homework Statement


A sample conaining both HCl and HNO3 had a density of 1.083g/ml. A 43.00 ml amount of this sample required 29.09 ml of 0.2828 M NaOH for titration. Another 43.00 ml amount of this sample required 7.88 ml of 0.1505 M AgNO3 for titration. Calculate the mass percent of HNO3 (molar mass = 63.018 g/mol) in the sample.


Homework Equations





The Attempt at a Solution


I know that you have to calculate the total number of mols of acid, but I'm not where to even start to do that.
 
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Start with writing all reaction equations. Three of them.
 
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