Chemistry: Net ionic equation of Fe,Cu,Zn with HCL

Click For Summary
SUMMARY

The discussion centers on the net ionic equations for the reactions of iron (Fe), copper (Cu), and zinc (Zn) with hydrochloric acid (HCl). The established net ionic equations are: for iron, Fe + 2 H+ → Fe2+ + H2; for zinc, Zn + 2 H+ → Zn2+ + H2. Copper does not react with HCl under normal circumstances, as it is lower than hydrogen in the reactivity series. However, the presence of nitrate ions in nitric acid can oxidize copper to Cu2+, which explains the observed blue solution during the experiment.

PREREQUISITES
  • Understanding of redox reactions
  • Familiarity with the reactivity series of metals
  • Knowledge of net ionic equations
  • Basic principles of electrochemistry
NEXT STEPS
  • Study the principles of balancing redox reactions
  • Learn about the reactivity series and its implications in chemical reactions
  • Explore the role of nitrate ions in oxidation reactions
  • Investigate the properties and reactions of transition metals with acids
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding metal reactivity and redox reactions in acid solutions.

wyeyip
Messages
1
Reaction score
0

Homework Statement


im given an experiment on reactivity series and required to write net ionic equation in the results.. I am kinda stuck in this reaction.. between this 3 metal.. iron, copper, and zinc.. reacting with nitric acid..


Homework Equations


the reaction was carried out with HCL also.. and these are the ionic equations i get.
Fe + 2 H+ = Fe + H₂
no reaction for copper.
Zn + 2 H+ = Zn + H₂

The Attempt at a Solution


well.. as far as i know.. copper won't react with nitric acid.. cos Cu is lower than H in the reactivity series.. but during experiment.. the Cu reacted and the solution turn blue.. this means copper is reacted.. so I am lost now..

can anyone give the solution for it?? the ionic equations..
 
Physics news on Phys.org
It's a redox reaction.
NO3− + 2 H+ + e− ⇄ NO2 + H2O E=+0.80V
Cu2+ + 2 e− ⇄ Cu(s) E=+0.34V
Hence, the nitrate ion is able to oxidise the Cu to Cu2+ ion.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
7
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
25K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
14
Views
3K