Chemistry - Stoichiometry - Some limiting reactants

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The discussion centers on stoichiometry calculations involving the reaction N2 + 3H2 -> 2NH3. The participant correctly calculated that 20.0 grams of hydrogen produces 112.5 grams of ammonia and that 46.2 grams of nitrogen react. However, an error was identified in the molar mass of nitrogen, which should be 28 g/mol instead of the incorrect value used. The discussion also touches on formatting text and using LaTeX for mathematical expressions.

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uchihajeff
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Did I answer these questions correctly?

5. In the reaction N2 + 3H2 -> 2NH3, if 20.0g of hydrogen reacts:
...a. How many grams of ammonia are produced?

...20.0g H2...|1 mol H2..|2 mol NH3.|...17.04g NH3
......|2.02g H2.| 3 mol H2..|...1 mol NH3
112.5 grams of ammonia are produced.

...b. How many grams of nitrogen react?

...20.0g H2 ...|1 mol H2..|1 mol N2.| 14.01g N2
......|2.02g H2.| 3 mol H2| 1 mol N2
46.2g of nitrogen react.

I think I did something wrong in part b. 20g +46.2g doesn't make 112.5g

btw, is there an easier way to format text (spaces) and how does (I think) latex work?
 
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Your method is correct in both parts.

Your only error (in part b) is with the molar mass of N2, which should be around 28. You forgot to double the atomic mass !
 
The only wat to format spaces is by enclosing the text within
Code:
 [/code ] tags.

For [itex]\LaTeX[/itex] see : [url]https://www.physicsforums.com/showthread.php?t=9021[/url]
 
Thanks a lot for your help with the problem and my other questions.


It's always those little errors that get me...
 

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