Chesmistry 12|VSEPER Problems|Quick Problems

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SUMMARY

The discussion focuses on the VSEPR (Valence Shell Electron Pair Repulsion) diagram for the molecule C2H2 (ethyne). The user is confused about the number of electron clouds around the central atom and the corresponding bond angles. It is clarified that C2H2 has 3 regions of electron density, leading to bond angles of 180 degrees due to its linear geometry. The discussion also highlights the composition of the triple bond in C2H2, which consists of 1 sigma bond and 2 pi bonds.

PREREQUISITES
  • Understanding of VSEPR theory
  • Knowledge of molecular geometry
  • Familiarity with sigma and pi bonds
  • Basic concepts of hybridization
NEXT STEPS
  • Study VSEPR theory in detail
  • Learn about hybridization in organic molecules
  • Explore molecular geometry for various hydrocarbons
  • Review the differences between sigma and pi bonds
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Chemistry students, educators, and anyone studying molecular geometry and bonding in organic chemistry will benefit from this discussion.

Raza
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Hi,
I am confused with this molecule's VSEPER diagram.
I was told to draw the VSEPER diagram for C2H2
This is what I drew:
http://www.albumtown.com/data/c44e503833b64e9f27197a484f4257c0/1142_p807888.jpeg
Then, it asked me to name the number and type of clouds on the central atom with the bond angles. This is where I am confused.
Does it have 5 clouds?
Is the bond angles 1200 in the plane and 900 in vertical?
 
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There should be a discussion of sigma and pi bonds in your chemistry textbook.

In H - C = C - H, the triple bond is composed of 1 sigma and two pi bonds. The H-C is a sigma bond.

There is a nice brief discussion of molecular shapes and bonds here -
http://www.chem.hope.edu/~chemboard/f05/messages/15/Molecular_Shapes_Lab-1308.pdf

See also -

http://www.chem.unl.edu/cak/bk5.htm

http://www.utdallas.edu/~parr/chm1341/13410618.html
 
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