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Chi-Square in Fraunhofer Approximation Lab Report

  1. Nov 28, 2011 #1
    Hello there if anyone could help me out with this question I would very much appreciate it. (Note this is my first post)

    For my optics lab Fraunhofer(single slit) diffraction patterns were observed(measured distance to screen(x) and had readings for intensity in the y direction.) I converted the y distances into degrees by taking inverse tangent (y/x). So for horizontal values I have my theta and vertical values my intensity. The experiment looks like this

    http://physics.wpi.edu/wiki/images/...ffraction.GIF/180px-SingleSlitDiffraction.GIF
    <br><img src="http://physics.wpi.edu/wiki/images/thumb/5/5e/SingleSlitDiffraction.GIF/180px-SingleSlitDiffraction.GIF" /><br>


    Anyway for my data, when plotted, I had the standard gaussian looking bell curve(i know it isnt a gaussian curve, but right now i cant think of better words to describe this). It looks like this

    http://cnx.org/content/m12915/latest/SingleSlitDiffraction__3.png
    <br><img src="http://cnx.org/content/m12915/latest/SingleSlitDiffraction__3.png" [Broken] /> <br>

    I was wondering how I calculate the uncertainty for these results. My professor mention a Chi-Square was possible. I dont see how I could calculate the theoretical value, even when I used the value for my experiment maximum intensity at I(0), for this experiment. This is the formula I am using for Fraunhofer approximation

    I(ϴ)=I(0) {sin(∏D(sin(ϴ)/λ) / (∏D(sin(ϴ)/λ) )}^2

    Where I(0) is the intensity for Ө=0(maximum intensity), λ is the wavelength, and D is the slit width.
     
    Last edited by a moderator: May 5, 2017
  2. jcsd
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