Laue Diffraction Intensity Distribution

In summary, the conversation was about using Laue photography to experimentally determine the atomic scattering factors for NaCl. This involved calculating intensity ratios using pixel values from a scanned x-ray film and using the equations (4⋅(fCl+fNa))2 and (4⋅(fCl-fNa))2 to find the ratio of scattering factors for Sodium and Chlorine. However, there were discrepancies in the intensity distribution that were not accounted for, and other factors such as spectral intensity and thermal motion of atoms could also affect the results. The conversation also referenced additional resources for more information on these factors.
  • #1
twosockz
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I am trying to experimentally determine the atomic scattering factors for NaCl using Laue photography. For an NaCl crystal, the intensity of the wave scattered at the unit cell is proportional to (4⋅(fCl+fNa))2 if h,k,l are even and to (4⋅(fCl-fNa))2 if h,k,l are odd. fNa and fCl are the atomic scattering factors which depend on sin(θ)/λ.

Therefore, I think that if sin(θ)/λ is approximately equal for two sets of h,k,l (one all even and one all odd), then we can combine the two equations to get:
Ieven+Iodd∝32⋅(fNa2+fCl2)
&
Ieven-Iodd∝64⋅fNa⋅fCl
(Is this correct so far?)

I plan to calculate the intensity ratios using pixel values of a scanned photographic x-ray film, as shown below. As such, we can then find the ratio of the scattering factors for Sodium and Chlorine using the equations above.

Attempting to use the (3,5,1) (odd) and (4,4,2) (even) Miller indices, which both have sin(θ)/λ ~ 0.05, I noticed a problem, as the second intensity equation implies that Ieven>Iodd, but, as shown below, this clearly isn't the case.

Are there any other factors affecting the intensity distribution that I am missing?

4JMhp8A.png


4JMhp8A
 

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  • #2
I suppose it will be a tremendous task to determine the atomic scattering factors for NaCl using Laue photography.

Quoting from [PDF]LAUE Laue Back-Reflection of X-Rays - University of Toronto Physics:

The size, intensity, and shape of a Laue spot depends on many factors, including the spectral intensity and angular dispersion of the X-ray beam, the perfection of the crystal, the thermal motion of the atoms in the crystal planes, the spectral absorption of beam and diffracted X-rays in the crystal, the angle of the spot,…. Only a few of these factors are discussed here; for more detail, see Cullity Ch. 4 and Preuss Ch. 2.3.

Here is the link to Cullity’s book:
B.D. Cullity, Elements of X-ray Diffraction, Addison Wesley 1956; https://archive.org/details/elementsofxraydi030864mbp
 
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What is Laue Diffraction Intensity Distribution?

Laue Diffraction Intensity Distribution is a phenomenon that occurs when a polycrystalline sample is exposed to a beam of X-rays. The X-rays interact with the atoms in the sample, diffracting in different directions and producing a unique pattern of intensities on a detector. This pattern can provide valuable information about the crystal structure and orientation of the sample.

How is Laue Diffraction Intensity Distribution different from other diffraction techniques?

Unlike other diffraction techniques, such as powder or single crystal diffraction, Laue Diffraction Intensity Distribution does not require the sample to be rotated. The polycrystalline nature of the sample allows for the X-rays to diffract in all directions, creating a comprehensive pattern of intensities on the detector.

What factors can affect the intensity distribution in Laue diffraction?

The intensity distribution in Laue diffraction can be affected by several factors, including the crystal structure of the sample, the wavelength of the X-rays, the orientation of the sample, and the quality of the X-ray beam. These factors can all impact the diffraction angles and intensities, resulting in a unique intensity distribution pattern for each sample.

How is the intensity distribution used to determine crystal structure?

The intensity distribution in Laue diffraction can be analyzed to determine the crystal structure of a sample. By comparing the observed intensity distribution with known patterns for different crystal structures, scientists can identify the crystal structure of the sample. This information can then be used to study the properties and behavior of the material.

What are some practical applications of Laue Diffraction Intensity Distribution?

Laue Diffraction Intensity Distribution has many practical applications in materials science, geology, and engineering. It can be used to identify unknown materials, study the crystal structure of natural and synthetic materials, and analyze the effects of different treatments or conditions on crystal structures. It is also a valuable tool in the development of new materials and technologies.

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