# CHI square independent test (small expected frequency)

1. Oct 11, 2014

### somecelxis

1. The problem statement, all variables and given/known data
the expected frequency for the age of (21-30, 31-36, more than or equal to 37) for operation is less than 5 , so combination of these numbers are required for the expected frequency to be more than or equal to 5 .
my question is which numbers should i combine?

would my ans be different?

2. Relevant equations

3. The attempt at a solution
in the solution, i combine the (21-30, 31-36, more than or equal to 37) for normal birth to get my Observed frequency = 34 and expected frequency = 38.37......

for operation, combine the (21-30, 31-36, more than or equal to 37) for normal birth to get my Observed frequency = 12 and expected frequency = 7.57......

can i combine less than( 21 and 21-30 ) , (31-36 , more than 37) ?

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2. Oct 11, 2014

### Mogarrr

This may be a solution to your problem.

I'm not sure if this was your plan. I would think if you combine the the rows 21-30 and 31-36, or 31-36 and 37+, then that'd fix the problem.

For your second question, why don't you just compute both and see if one contradicts the decision of the other?