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CHI square independent test (small expected frequency)

  1. Oct 11, 2014 #1
    1. The problem statement, all variables and given/known data
    the expected frequency for the age of (21-30, 31-36, more than or equal to 37) for operation is less than 5 , so combination of these numbers are required for the expected frequency to be more than or equal to 5 .
    my question is which numbers should i combine?

    would my ans be different?

    2. Relevant equations


    3. The attempt at a solution
    in the solution, i combine the (21-30, 31-36, more than or equal to 37) for normal birth to get my Observed frequency = 34 and expected frequency = 38.37......

    for operation, combine the (21-30, 31-36, more than or equal to 37) for normal birth to get my Observed frequency = 12 and expected frequency = 7.57......

    can i combine less than( 21 and 21-30 ) , (31-36 , more than 37) ?
     

    Attached Files:

  2. jcsd
  3. Oct 11, 2014 #2
    This may be a solution to your problem.

    I'm not sure if this was your plan. I would think if you combine the the rows 21-30 and 31-36, or 31-36 and 37+, then that'd fix the problem.

    For your second question, why don't you just compute both and see if one contradicts the decision of the other?
     
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