Chinese Remainder Theorem: Divisibility in Arithmetic

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SUMMARY

The discussion focuses on solving a system of congruences using the Chinese Remainder Theorem (CRT). The specific problem involves finding integer solutions for the equations X≡2(mod5) and X≡1(mod6). The participant successfully derived a unique solution set S={(1,1)} by substituting X=5t+2 into the second congruence and simplifying. The CRT provides a systematic method for solving such modular arithmetic problems efficiently.

PREREQUISITES
  • Understanding of modular arithmetic
  • Familiarity with the Chinese Remainder Theorem
  • Basic algebraic manipulation skills
  • Knowledge of integer solutions in congruences
NEXT STEPS
  • Study the proof and applications of the Chinese Remainder Theorem
  • Learn about solving systems of linear congruences
  • Explore advanced topics in modular arithmetic, such as multiplicative inverses
  • Practice solving similar problems using different moduli
USEFUL FOR

Students in mathematics, particularly those studying number theory, educators teaching modular arithmetic, and anyone interested in solving congruences using the Chinese Remainder Theorem.

mtayab1994
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Chinese remainder theorem help

Homework Statement



Solve in [tex]Z^{2}:6x-5y=1[/tex]

Conclude the solution to the system:

X≡2(mod5) , X≡1(mod6)

The Attempt at a Solution



1- solved the equation and found one unique solution which was S={(1,1)}

Given:
X≡2(mod5) , X≡1(mod6)

X≡2(mod5) means X=5t+2

X≡1(mod6) means 5t+2=1(mod6) which is 5t=-1(mod6) But how can i proceed from here on?
 
Last edited:
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Solved it :)
 

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