Understanding Conventional Current and Electron Flow

  • Thread starter Thread starter Oerg
  • Start date Start date
  • Tags Tags
    Current
Click For Summary
SUMMARY

This discussion clarifies the distinction between conventional current and electron flow in direct current (D.C.) circuits. Conventional current is defined as the flow of positive charge from higher potential to lower potential, while electron flow occurs in the opposite direction, moving from lower potential to higher potential. The confusion arises from the negative charge of electrons, which leads to the misconception about their movement in relation to potential differences. Understanding this concept is crucial for grasping the principles of electrical circuits and heat loss due to resistance.

PREREQUISITES
  • Basic understanding of electrical circuits
  • Knowledge of potential difference and voltage
  • Familiarity with charge carriers in conductors
  • Concept of heat loss in electrical components
NEXT STEPS
  • Study the principles of D.C. circuit analysis
  • Learn about Ohm's Law and its applications
  • Explore the concept of resistivity and heat generation in conductors
  • Investigate the role of charge carriers in semiconductor physics
USEFUL FOR

Students of electrical engineering, educators teaching circuit theory, and anyone seeking to deepen their understanding of current flow and its implications in electrical systems.

Oerg
Messages
350
Reaction score
0
Conventional Current?

Hi guys,

I have a pretty simple conceptual problem that has been bugging me for a while. In a D.C. circuit, the conventional current moves from higher potential to lower potential. But the electron flow is opposite that of the conventional current. That means that the electrons move from lower potential to higher potential?? How can that be possible, since the heat loss in the wires should arise in electron flow from higher to lower potential.
 
Physics news on Phys.org
When a charge moves from potential V1 to V2, work done = q(V2-V1). This work done is manifested as heat loss. Since q for an electron is negative, V2-V1 is also negative to make work done positive, => v2<V1.
 
ohhhhhhhhhhhhhh so you can consider charges with the polarity in the electrostatic equations! Well, i guess my teacher was too lazy and taught the topic using modulus.
 

Similar threads

  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K